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The topic of this article may not meet Wikipedia's. Please help to establish notability by citing that are of the topic and provide significant coverage of it beyond a mere trivial mention. If notability cannot be established, the article is likely to be, or.Find sources: – ( October 2012) CellMax Technologies, also known as Cellmax, is a Swedish developer and manufacturer of efficient used for s in networks.CellMax Technologies was founded in 2001 and is headquartered in the Swedish ICT cluster Kista, outside, with subsidiaries in Singapore and the USA. In 2012, CellMax Technologies opened a factory outside.Cellmax was named a Deloitte Technology Fast 500 EMEA 2011 company as one of the fastest growing technology companies in Europe, the Middle East and Africa.In 2012, Cellmax invested 20 million SEK in a research center and antenna laboratory in Kista. The plant is described as one of the world's most modern and will be used for research and development of the 'next generation' of base station antennas. Of Sweden and Sweden’s opened the plant in summer 2012 along with global industry leaders in telecommunications, and foreign ambassadors.

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Yes, but ret 2 also removes 2 bytes of parameters from the stack. Presumably, your function was called like: push someparametercall FunctionAt this point, a cdecl function - a 'caller cleans up' function (Generally used by C) - would require add sp, 2 to 'clean up the stack', removing the parameter. Such a function would end in a plain ret.A stdcall function, which is what you've got, is a 'callee cleans up' function (used by Windows APIs, for example) doesn't require the add sp, 2 - it has been done by the ret 2.If you're not aware of it, call puts the return address on the stack (and ret pops it off), so you can't just pop to get the parameter inside your function. Lets say I have a procedure to add two words and leave the sum in EAX.

The words are arguments I want to pass to the procedure on the stack. I.e: push word1push word2call addtwobThe procedure would look something like: addtwob procpush ebpmov ebp,espmov eax, ebp+6add eax, ebp+8pop ebpret 4Endpebp+6 and ebp+8 address word2 and word1 on the stack.ret 4 just returns like usual but then adds 4 to the stack pointer ( esp) so you don't have to pop word2 pop word1 off the stack after returning from the call, therefore it cleans/balances the stack without needing to pop the previous pushes. As alex said, it means RETURN.In x86 assembly, when the compiler reaches to this line (at the end of a subroutine, for example), it pops the last value from the stack, which supposed to be the returning address, and assigned it to IP register. You can understand that better by writing a simple assembler code and compile it with Turbo Debugger.

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There's a GUI for assembler if you are new to that. You can find the GUI.When you are poping and pushing values from and to the stack when you are in a subroutine, you should store the returning address, because in the end of the subrouting you need to push it back in to the stack before the return line.Good luck! You seem to be asking about a near return with an operand for x8664. For x86 32 bit 'The optional numeric (16- or 32-bit) parameter to ret specifies the number of stack bytes or words to be released after the return address is popped from the stack. Typically, these bytes or words are used as input parameters to the called procedure. '-so first it pops the return address then the optional number refers to the number of BYTES to increment the stack after popping the return address.ret 4 would be a total of esp+=8 in 32-bit mode, including popping the 4-byte return address and 4 bytes that the caller had pushed.